4x^2(256)=(1/16)^2x

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Solution for 4x^2(256)=(1/16)^2x equation: 


x in (-oo:+oo)

4*256*x^2 = (1/16)^2*x // - (1/16)^2*x

4*256*x^2-((1/16)^2*x) = 0

1024*x^2-1/256*x = 0

DELTA = (-1/256)^2-(0*4*1024)

DELTA = 1/65536

DELTA > 0

x = ((1/65536)^(1/2)+1/256)/(2*1024) or x = (1/256-(1/65536)^(1/2))/(2*1024)

x = 1/262144 or x = 0

x in { 0, 1/262144 }

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